Question
Download Solution PDFA vertical gate closes a horizontal tunnel 4 m high and 3 m wide running full with water. The bottom of the vertical gate is located at a distance of 8 m from the free water surface. Determine the total fluid force( in kN) acting on the gate. Take g as 9.81 m/s2
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Pressure intensity is given as, \(P=\rho gh\)
where h is the height of water
To calculate the force acting on the surface, \(X=P\times A\)
where A = projected area
Calculation:
Given: A = \(4\times3=12m^2\); h = \(4+2=6m\)
Pressure intensity will be \(P=9.81\times6=58.86kN/m^2\)
Force acting on the gate will be \(X=58.86\times12=706kN\)
Last updated on May 28, 2025
-> SSC JE notification 2025 for Civil Engineering will be released on June 30.
-> Candidates can fill the SSC JE CE application from June 30 to July 21.
-> The selection process of the candidates for the SSC Junior Engineer post consists of Paper I, Paper II, Document Verification, and Medical Examination.
-> Candidates who will get selected will get a salary range between Rs. 35,400/- to Rs. 1,12,400/-.
-> Candidates must refer to the SSC JE Previous Year Papers and SSC JE Civil Mock Test, SSC JE Electrical Mock Test, and SSC JE Mechanical Mock Test to understand the type of questions coming in the examination.
-> The Staff Selection Commission conducts the SSC JE exam to recruit Junior Engineers in different disciplines under various departments of the Central Government.