A varies directly as the positive square root of B, and inversely as the cube of C. If A = 15, when B = 27 and C = 2, then find B when A = 9 and C = 2.

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SSC CGL 2022 Tier-I Official Paper (Held On : 05 Dec 2022 Shift 2)
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Answer (Detailed Solution Below)

Option 2 :
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PYST 1: SSC CGL - General Awareness (Held On : 20 April 2022 Shift 2)
25 Qs. 50 Marks 10 Mins

Detailed Solution

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Given:

A varies directly as the positive square root of B.

A = 15, when B = 27 and C = 2.

Concept used:

If P ∝ Q and P ∝ R, then P ∝ QR and P = H × QR. (Here, H is a constant)

Calculation:

​According to the question,

∝  and A ∝ 1/C3

So, A ∝ 

⇒ A = k ×       ....(1) (Here, k is a constant)

Now putting A = 15, B = 27 and C = 2 in (1),

A = k × 

⇒ 15 = k × 

⇒ k = 

⇒ k = 

Now when A = 9 and C = 2,

A = k × 

⇒ 9 =  × 

⇒  = 9/5

⇒ B/3 = 81/25

⇒ B = 243/25

∴ The value of B is .

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