A train leaves station A towards station B at the speed of 50 km/hr. After half an hour, another train leaves station B towards station A at 150 km/hr. The distance between the stations is 725 km. The distance of the point from station A where the two trains are to meet is:

Question

Question

This question was previously asked in

RRB NTPC CBT-I Official Paper (Held On: 28 Dec 2020 Shift 1)

Answer 1

Given:

The speed of train which leaves station A = 50 km/hr

The speed of train which leaves station B = 150 km/hr

The distance between the two stations A and B = 725 km

Formula used:

Distance = Speed × Time

Relative Speed ( in opposite direction) = Speed I + Speed II

Meeting Time = Distance between the trains/ Relative Speed

Solution:

Relative speed of both the trains going in opposite direction = 50 km/h + 150 km/h

⇒ 200 km/h

Distance between the trains after half an hour of train leaving station A = 725 km - 50 km/h × 1/2 hours = 700 km

Meeting time = 700 km / 200 km/h = 7/2 hours

∴ Distance from station A where two trains are to meet = 25 km + 50 km/h × 7/2 hours = 200 km