Question
Download Solution PDFA thief is noticed by a policeman from a distance of 500 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 17 km/h and 20 km/h, respectively. What is the distance between them after 8 minutes?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Distance between policeman and thief in the starting = 500 m
Speed of policeman = 20 km/hr
Speed of thief = 17 km/hr
Concept: /Formula:
If the speed of a policeman and thief is x km/hr and y km/hr, then
Relative speed, if same directions = (x – y) km/hr
Distance between them after n hrs = (x – y) × n
1 km/hr = 5/18 m/sec
1 min = 60 sec
Calculation:
8 min = 8 × 60 = 480 seconds
Distance between policeman and thief in starting = 500 m
Relative speed of policeman and thief, if same directions = (20 – 17) = 3 × (5/18) = (5/6) m/sec
Distance covered in 480 seconds = (5/6) × 480 = 400 m
Distance between them after 480 seconds= 500 – 400 = 100 m
∴ Distance between them after 8 min is 100 m.
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