Question
Download Solution PDFA soap bubble of radius R is surrounded by another soap bubble of radius 2R, as shown. Take surface tension = S. Then the pressure inside the smaller soap bubble, in excess of the atmospheric pressure, will be
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept: Excess pressure inside a soap bubble is given by 4S / R due to two surfaces (inner and outer) under surface tension.
Let:
P0 = Atmospheric pressure
P1 = Pressure inside the larger bubble (radius 2R)
P2 = Pressure inside the smaller bubble (radius R)
Pressure inside the larger bubble:
P1 = P0 + 4S / (2R) = P0 + 2S / R
Pressure difference between smaller and larger bubble:
P2 - P1 = 4S / R
Substituting from (i) and (ii):
P2 - P0 = (P2 - P1) + (P1 - P0)
= (4S / R) + (2S / R) = 6S / R
Answer: Option 3) 6S / R
Last updated on Jun 6, 2025
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