A series RLC circuit has R = 50 Ω, XC = 90 Ω and XL = 30 Ω. The impedance of the circuit is:

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NHPC JE Electrical 5 April 2022 (Shift 1) Official Paper
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  1. 50 - j 60 Ω
  2. -50 - j 60 Ω
  3. -50 + j 60 Ω
  4. 50 + j 60 Ω

Answer (Detailed Solution Below)

Option 1 : 50 - j 60 Ω
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Detailed Solution

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Concept:

For a series RLC circuit, the net impedance is given by:

Z = R + j (XL - XC)

XL = Inductive Reactance given by:

XL = ωL

XC = Capacitive Reactance given by:

XC = 1/ωC

Impedance = Resistance + j Reactance

The magnitude of the impedance is given by:

\(|Z|=\sqrt{R^2+(X_L-X_C)^2}\)

Application:

Given:

R = 50 Ω,

XC = 90 Ω and,

XL = 30 Ω

From the above concept, impedance (Z) is given as,

Z = R + j (XL - XC)

or, Z = 50 + j(30- 90) = (50 - j60) Ω

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