A rectangular steel bar of size 100 mm × 25 mm × 20 mm has strains in x, y and z directions, 0.0065, 0.0025 and 0.002 respectively. The change in volume due to these strains is

This question was previously asked in
HPCL Engineer Mechanical 12 Aug 2021 Official Paper (Shift 1)
View all HPCL Engineer Papers >
  1. 366.6 mm3
  2. 625 mm3
  3. 550 mm3
  4. 183.3 mm3

Answer (Detailed Solution Below)

Option 3 : 550 mm3
Free
Environmental Engineering for All AE/JE Civil Exams Mock Test
10.4 K Users
20 Questions 20 Marks 20 Mins

Detailed Solution

Download Solution PDF

Concept:

Volumetric strain:

It is defined as the ratio of change in volume to the initial volume of the body. It is equal to the sum of strain in all directions.

ϵv = ϵx + ϵy + ϵz  

It is also known as the ratio of change of volume to original volume.

\(\epsilon_v=\frac{\Delta V}{V}\)

Calculation:

Given:

Volume = 100 mm × 25 mm × 20 mm, 

ϵx = 0.0065, ϵy = 0.0025, ϵz = 0.002

ϵv = ϵx + ϵy + ϵz  

ϵv = 0.0065 + 0.0025 + 0.002 = 0.011

\(\epsilon_v=\frac{\Delta V}{V}\)

\({\Delta V}=\epsilon_v{V}\)

\({\Delta V}=0.011\times{100\times25\times20}=550\;mm^3\)

Latest HPCL Engineer Updates

Last updated on Jun 2, 2025

-> HPCL Engineer 2025 notification has been released on June 1, 2025.

-> A total of 175 vacancies have been announced for the HPCL Engineer post in Civil, Electrical, Mechanical, Chemical engineering.

-> HPCL Engineer Online application will be activated from 1st June 2025 to 30th June 2025.

-> Candidates with a full-time engineering discipline in the relevant stream are eligible to apply.

-> The selection will be based on a Computer Based Test Group Task and/or Interview. Prepare for the exam using HPCL Engineer Previous Year Papers.

More Volumetric Strain Questions

Get Free Access Now
Hot Links: teen patti all teen patti star apk teen patti joy 51 bonus teen patti joy mod apk teen patti all games