A five-digit number 32054 is divisible by 11. If the digits are rearranged in increasing order, then the new number which is formed will be divisible by:

Given

A five-digit number: 32054

Concept:

For a number to be divisible by 11, the difference between the sum of digits in the odd positions and even positions must be a multiple of 11 or 0.

For a number to be divisible by 5, the last digit of a number should 0 or 5.

For a number to be divisible by 3, the sum of all digit of a number should be multiple of 3.

For a number to be divisible by 2, the unit digit of a number should be even number (0, 2, 4, etc)

Calculation:

Rearranging the digits in ascending order, we get: 02345

Sum of digits of number = 0 + 2 + 3 + 4 + 5 = 14, number is not divisible by 3.

Difference between the sum of digits at odd positions(5 + 3 + 0) and the sum of digits at even positions(4 + 2) = 8 - 6 = 2, number is not divisible by 11

Last digit is 5 i.e. odd, not divisible by 2.

Since the last digit is 5, the number is divisible by 5.

Therefore, the number formed by rearranging the digits in increasing order is divisible by 5.