A filament lamp of 40 W, 110 V is connected in series with resistance R. If the supply voltage is 230 V, the value of resistance R should be: 

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  1. 1340 ohm
  2. 130 ohm
  3. 240 ohm
  4. 330 ohm

Answer (Detailed Solution Below)

Option 4 : 330 ohm
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Detailed Solution

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Concept

According to the KVL, the total voltage drop in a closed circuit is zero.

ΣV = 0

By Ohm's Law, the value of resistance is given by:

\(R={V\over I}\)

Calculation

F1 Madhuri Engineering 10.02.2023 D2

The voltage across the resistance (R) is given by:

VR = 230 - 110 V = 120 V

The current across the bulb is given by:

\(I={P\over V}\)

\(I={40\over 110}={4\over 11}A\)

Since the bulb and resistance are in series, the current across both of them will be the same.

The value of R is given by:

\(R={120\over 4/11}\)

\(R={120\times 11\over 4}=330 \Omega \)

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