Question
Download Solution PDFA 64kΩ resistor has a specified maximum power dissipation of 1000 watts. The maximum current that may be passed through the resistor is ________.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The power across the resistance is given by:
\(P={I^2\times R}\)
where, P = Power
I = Current
R = Resistance
Calculation
Given, P = 1000 W
R = 64 kΩ
\(1000={I^2\times 64\times 10^3}\)
\(R={1\over 8}\space \Omega\)
Last updated on May 29, 2025
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