Multiplexer MCQ Quiz in తెలుగు - Objective Question with Answer for Multiplexer - ముఫ్త్ [PDF] డౌన్‌లోడ్ కరెన్

Given maxterm

F (A,B,C,D) = π (1,5,12,15)

The minterms of the given max terms will be

f (A,B,C,D) = Σm (0,2,3,4,6,7,8,9,10,11,13,14) 

Therefore, the correct inputs to pins 0, 1, 2, 3, 4, 5, 6, 7 in order is D’, 1, D’, 1, 1, 1, D, D’

\(F = \overline {{s_1}} \overline {{s_0}} \left( {{I_0}} \right) + \overline {{s_1}} {s_0}\left( {{I_1}} \right) + {s_1}\overline {{s_0}} \left( {{I_2}} \right) + {s_1}{s_0}\left( {{I_3}} \right)\)

= x̅ y̅ (0) + x̅ y (1) + x y̅ (1) + xy (1)

= x̅ y + x y̅ + xy

= x̅ y + x (y̅ + y)

= x + x̅ y = x + y

Concept:

• A multiplexer is Many to one data selector.
• A multiplexer selects one of the many data available at its input depending on the bits on the select line.
• For 2n inputs, there are n select lines that determine, which input is to be connected to the output.

Application:

A 4 × 1 multiplexer selects one of the 4 inputs and presents it to the output, i.e.

2ⁿ = 4

n = log₂4 = log₂2²

n = 2log₂2

n = 2

So the number of select lines will be 2.

The block diagram representation of a 4 × 1 multiplexer is as shown:

S₁ and S₀ indicate the select lines.

Concept:

Multiplexer: It is a combinational circuit that selects binary information from one of many input lines and directs it is to single output lines.

The selection of particular input lines is controlled by a set of selection lines.

\(Y = {\bar S_1}{\bar S_0}\;{I_0} + {\bar S_1}{S_0}{I_1} + {S_1}{\bar S_0}{I_2} + {S_1}{S_0}{I_3}\)

Calculation:

From the given multiplexer,

f = w̅₁w̅₄ (I₀) + w̅₁w₄(I₁) + w₁w̅₄ (I₂) + w₁w₄ (I₃)

Given that the output is,

f = w̅₁w̅₂w̅₄w̅₅ + w₁w₂ + w₁w₃ + w₁w₄ + w₃w₄w₅

Now, we need to express every term in terms of w₁ and w₄ as these are the inputs of selection lines

f = w̅₁ w̅₄ (w̅₂w̅₅) + w₁w₂ (w̅₄ + w₄) + w₁w₃ (w̅₄ + w₄) + w₁w₄ + w₃w₄w₅ (w̅₁ + w₁)

= w̅₁w̅₄ (w̅₂w̅₅) + w₁w₂w̅₄ + w₁w₂w₄ + w₁w₃w̅₄ + w₁w₃w₄ + w₃w₄w₅w̅₁ + w₃w₄w₅w₁ + w₁w₄

= w̅₁w̅₄ (w̅₂w̅₅) + w̅₁w₄ (w₃w₅) + w₁w̅₄ (w₂ + w₃) + w₁w₄ (w₂ + w₃ + w₃w₅ + 1)

= w̅₁w̅₄ (w̅₂w̅₅) + w̅₁w₄ (w₃w₅) + w₁w̅₄ (w₂ + w₃) + w₁w₄ (1)

I₀ = w̅₂w̅₅ → Box 1 represents NOR gate

I₁ = w₃w₅ → Box 2 represents AND gate

I₂ = w₂ + w₃ → Box 3 represents OR gate

• Multiplexing is the process of transmission of information from more than one source into a single signal over a shared medium.
• The primary advantage of multiplexing is that we can transmit a large number of signals through a single medium.
• The channel can be a physical medium like a coaxial, metallic conductor or a wireless link.
• The block diagram showing frequency division multiplexing is as shown:

           ​

Multiplexer:

• A multiplexer is Many to one data selector.
• A multiplexer selects one of the many data available at its input depending on the bits on the select line.
• For 2m inputs, there are m select lines that determine, which input is to be connected to the output, i.e.

          Number of control lines = log2(number of input lines)

So, m control lines can create 2m combinations

Example:

A 16 × 1 multiplexer selects one of the 16 inputs and presents it to the output, i.e.

2m = 16

m = log216 = log224

m = 4log22

m = 4

So the number of select lines will be 4.

F (A, B, C, D) = Σm (0, 1, 2, 4, 6, 9, 12, 14)

To implement the above Boolean expression using a 8 : 1 multiplexer, the selection lines are B, C and D.

Now drawing the Truth table by taking A as MSB.

From the above truth table,

\({I_0} = \;\bar A,{I_1} = 1,{I_2} = \bar A,{I_3} = 0,{I_4} = 1,{I_5} = 0,{I_6} = 1,{I_7} = 0\)

Now, the required 8:1 multiplexer is as shown below.

The correct answer is option (1)

Concept:

Multiplexer:

• It is type of combinational circuit for which the present output depends only on the present input.
• It is also known as memoryless circuit because there are no memory element to store the past output.
• A multiplexer is a many to one data selector.
• It selects one of the many data available at its input depending on the bits of the select lines.
• For 2ⁿ inputs, there are n select lines that determine which input is to be connected to the output.

In the given multiplexer circuit, we have 8 input lines.

∴ 2ⁿ = 8

2ⁿ = 2³

By comparing exponents on both sides we get;

n = 3

In conclusion, the total number of select lines is (n) = 3

Multiplexer: 

• A multiplexer is Many to one data selector.
• A multiplexer selects one of the many data available at its input depending on the bits on the select line.
• For selecting eight inputs, there are three data select lines that must be used. The multiplexer requires the data select lines. We have three data select lines for eight inputs, and it's an 8:1 multiplexer.

Example:

An 8 × 1 multiplexer selects one of the 8 inputs and presents it to the output, i.e.
2^m  = 8
m = log₂ 8 = log₂ (2³)
m = 3log₂ 2
m = 3

So, the number of data select lines are 3.

Concept:

For a 2 × 1 MUX is shown above, the output function F is expressed as:

F = S̅1 I0 + S1I1

Application:

Let the Output of Multiplexer is Y.

Y = X̅.X + X.X̅.

Y = 0

Y₀ = 0 ⊙ X̅

With X = a ⊕ b, X̅ = a ⊙ b

Y0 = 0 ⊙ (a ⊙ b)