Bar Graph and Line Graph MCQ Quiz in मल्याळम - Objective Question with Answer for Bar Graph and Line Graph - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക
Last updated on Mar 17, 2025
Latest Bar Graph and Line Graph MCQ Objective Questions
Top Bar Graph and Line Graph MCQ Objective Questions
Bar Graph and Line Graph Question 1:
Comprehension:
Direction: Read the following Bar graph carefully and answer the following questions
The Bar graph shows the number of BMW and Audi cars in 4 different cities.
The Line graph shows the Percent of men and women who have car in 4 different cities.
What is average of women who have the BMW cars in all the cities?
Answer (Detailed Solution Below)
Bar Graph and Line Graph Question 1 Detailed Solution
Concept used:
Average = Total women / Number of cities
Calculations:
Percent of Men who have BMW car in Jaipur = 70%
⇒ Percent of Women who have BMW car in Jaipur = (100 - 70)% = 30%
Number of Women who have BMW in Jaipur = 200 × 30 / 100 = 60
Percent of Women who have BMW car in Delhi = 20%
Number of Women who have BMW in Delhi = 175 × 20 / 100 = 35
Percent of Women who have BMW car in Mumbai = 60%
Number of Women who have BMW in Mumbai = 275 × 60 / 100 = 165
Percent of Women who have BMW car in Udaipur = 40%
Number of Women who have BMW in Udaipur = 150 × 40 / 100 = 60
Average of Women = Total Women / Numbers of Cities
⇒ (60 + 35 + 165 + 60) / 4 = 320 / 4 = 80
∴ The average of women who have BMW cars in all the cities is 80
Bar Graph and Line Graph Question 2:
In this bar graph represent the total number of vacant seats in SSC and Bank.
What is the percentage of SSC vacant seats out of total vacant seats in these five years?
Answer (Detailed Solution Below)
Bar Graph and Line Graph Question 2 Detailed Solution
Given:
Total Vacant seats in SSC and Bank in five years.
Calculation:
Total Vacant seats in SSC in this five years = 750 +900 + 700 + 800 + 640
⇒ 3790
Total Vacant seats in Bank in this five years = 480 + 500 + 750 + 820 +550
⇒ 3100
Total Vacant seats in Bank and SSC in this five year = 3790 + 3100 = 6890
Percentage of SSC = (3790 × 100) / 6890
⇒ 55 %
Percentage of Vacant seats in SSC in this five years = 55 %
Bar Graph and Line Graph Question 3:
Study the following percentage graph and answer the question,
Total Expenditure of the company = 100,000
The Total Expenditure of the company is how many times of its total expenditure of Research and Salary?
Answer (Detailed Solution Below)
Bar Graph and Line Graph Question 3 Detailed Solution
Given:
Total Expenditure of the company = 100,000
Solution:
Total Expenditure of Research = 100,000 × 5%
⇒ 5000
Total Expenditure of Salary = 100,000 × 20%
⇒ 20000
Total Expenditure of Research and Salary = 5000 + 20000
⇒ 25000
Total Expenditure of The company = 100,000
⇒ Total expenditure of the company / Total expenditure of Research and Salary
⇒ 100,000 / 25000 = 4
Total Expenditure of the company is 4 times of its total expenditure of Research and Salary.
Bar Graph and Line Graph Question 4:
Data of students (in Percentage) Who get Admission after Matriculation.
If the Total number of Students in a School is 280. What is The Difference between Arts students and Commerce students?
Answer (Detailed Solution Below)
Bar Graph and Line Graph Question 4 Detailed Solution
Given:
The Total number of a Student of a school is 280.
Solution:
The number of students in Arts = 55% of 280
⇒ 154
The number of students in Commerce = 15% of 280
⇒ 42
Difference between Arts students and Commerce students = 154 - 42
⇒ 112
Difference between Arts students and Commerce students = 112
Bar Graph and Line Graph Question 5:
Comprehension:
Directions: Study the given graphs and answer the question that follows.
The graphs show total number of students and number of boys(%) in five schools A, B, C, D and E.
The total number of girls in school B is x and the total number of boys in school D is y. Which of the following option is correct?
Answer (Detailed Solution Below)
Bar Graph and Line Graph Question 5 Detailed Solution
Given:
|
Schools |
Total students |
Boys |
|
A |
400 |
33% |
|
B |
420 |
55% |
|
C |
520 |
35% |
|
D |
630 |
60% |
|
E |
440 |
50% |
Calculations:
|
Schools |
Total students |
Boys |
Girls |
|
A |
400 |
33% |
(100% – 33%) = 67% |
|
B |
420 |
55% |
(100% – 55%) = 45% |
|
C |
520 |
35% |
(100% – 35%) = 65% |
|
D |
630 |
60% |
(100% – 60%) = 40% |
|
E |
440 |
50% |
(100% – 50%) = 50% |
The total number of girls in school B is x = 45% of 420 = 189
The total number of boys in school D is y = 60% of 630 = 378
∴ x = 189, y = 378.
Bar Graph and Line Graph Question 6:
Data Show the % of different sect of Christian Population.
If The total population of Christian is 2,18,000. Find out the number of Orthodox in Christian?
Answer (Detailed Solution Below)
Bar Graph and Line Graph Question 6 Detailed Solution
Given:
Total number of Christian = 2,18,000
Solution:
The % of Orthodox in Christian = 12%
Total number of Christian (100%) = 2,18,000
Total number of Orthodox in Christian = (2,18,000 / 100) × 12
⇒ 26160
Total number of Orthodox in Christian = 26,160
Bar Graph and Line Graph Question 7:
Comprehension:
Instructions: Study the graph below and answer the question based on it.
The number of vehicles manufactured by the company X and Y from 2001 to 2006 has been given (in thousands).
What is the difference between the number of vehicles produced by Company X in the year 2001 and 2002? (In thousand)
Answer (Detailed Solution Below)
Bar Graph and Line Graph Question 7 Detailed Solution
Calculation:
⇒ Number of vehicles produced by Company X in 2001 = 57
⇒ Number of vehicles produced by Company X in 2002 = 61
⇒ Difference = 61 - 57 = 4
∴ The correct answer is Option 4).
Bar Graph and Line Graph Question 8:
Comprehension:
Direction: Read the following Bar graph carefully and answer the following questions
The Bar graph shows the number of BMW and Audi cars in 4 different cities.
The Line graph shows the Percent of men and women who have car in 4 different cities.
Find the degree value of all men who have BMW cars in all cites with respect to total number of cars in all four cities.
Answer (Detailed Solution Below)
Bar Graph and Line Graph Question 8 Detailed Solution
Concept used:
Degree = (Total Men who have BMW / Total number of cars) × 360°
Calculations:
Number of men who have BMW in Jaipur = 200 × (70 / 100) = 140
Number of men who have BMW in Delhi = 175 × (80 / 100) = 140
Number of men who have BMW in Mumbai = 275 × (40 / 100) = 110
Number of men who have BMW in Udaipur = 150 × (60 / 100) = 90
Total number of men who have BMW cars in all the cities = 140 + 140 + 110 + 90 = 480
Total number of cars in all the cities = 200 + 125 + 175 + 250 + 275 + 300 + 150 + 125 = 1600
Degree value of men who have BMW cars = (Total Men who have BMW / Total number of cars) × 360°
⇒ (480 / 1600) × 360° = 108°
∴ The degree value of men who have BMW cars is 108°Bar Graph and Line Graph Question 9:
Comprehension:
Direction: Read the following Bar graph carefully and answer the following questions
The Bar graph shows the number of BMW and Audi cars in 4 different cities.
The Line graph shows the Percent of men and women who have car in 4 different cities.
Find the ratio of men who have BMW car with the women who have Audi car in all four cities.
Answer (Detailed Solution Below)
Bar Graph and Line Graph Question 9 Detailed Solution
Calculations:
Number of men who have BMW in Jaipur = 200 × (70 / 100) = 140
Number of men who have BMW in Delhi = 175 × (80 / 100) = 140
Number of men who have BMW in Mumbai = 275 × (40 / 100) = 110
Number of men who have BMW in Udaipur = 150 × (60 / 100) = 90
Total number of men who have BMW call in all the cities = 140 + 140 + 110 + 90 = 480
Number of Women who have Audi in Jaipur = 125 × 40 / 100 = 50
Number of Women who have Audi in Delhi = 250 × 20 / 100 = 50
Number of Women who have Audi in Mumbai = 300 × 60 / 100 = 180
Number of Women who have Audi in Udaipur = 125 × 80 / 100 = 100
Total Number of Women who have Audi cars in four cities = 50 + 50 + 180 + 100 = 380
Hence ratio of men who have BMW car with the women who have Audi car in all four
⇒ 480 ∶ 380
⇒ 24 ∶ 19
Bar Graph and Line Graph Question 10:
Comprehension:
Directions: Study the given graphs and answer the question that follows.
The graphs show total number of students and number of boys(%) in five schools A, B, C, D and E.
Find the difference between the number of boys in school B and the number of boys in school D.
Answer (Detailed Solution Below)
Bar Graph and Line Graph Question 10 Detailed Solution
Given:
|
Schools |
Total students |
Boys |
|
A |
400 |
33% |
|
B |
420 |
55% |
|
C |
520 |
35% |
|
D |
630 |
60% |
|
E |
440 |
50% |
Calculation:
Number of boys in school B = 55% of 420 = 231
Number of boys in school D = 60% of 630 = 378
Required difference = 378 - 231 = 147
∴ 147