Bar Graph and Line Graph MCQ Quiz in मल्याळम - Objective Question with Answer for Bar Graph and Line Graph - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക

Last updated on Mar 9, 2025

നേടുക Bar Graph and Line Graph ഉത്തരങ്ങളും വിശദമായ പരിഹാരങ്ങളുമുള്ള മൾട്ടിപ്പിൾ ചോയ്സ് ചോദ്യങ്ങൾ (MCQ ക്വിസ്). ഇവ സൗജന്യമായി ഡൗൺലോഡ് ചെയ്യുക Bar Graph and Line Graph MCQ ക്വിസ് പിഡിഎഫ്, ബാങ്കിംഗ്, എസ്എസ്‌സി, റെയിൽവേ, യുപിഎസ്‌സി, സ്റ്റേറ്റ് പിഎസ്‌സി തുടങ്ങിയ നിങ്ങളുടെ വരാനിരിക്കുന്ന പരീക്ഷകൾക്കായി തയ്യാറെടുക്കുക

Latest Bar Graph and Line Graph MCQ Objective Questions

Top Bar Graph and Line Graph MCQ Objective Questions

Bar Graph and Line Graph Question 1:

Comprehension:

Direction: Read the following Bar graph carefully and answer the following questions

The Bar graph shows the number of BMW and Audi cars in 4 different cities.

F1 Sanyukta Others 26.5.22 G1

The Line graph shows the Percent of men and women who have car in 4 different cities.

Banking Akash gautam 26.05.2023 G2

What is average of women who have the BMW cars in all the cities?

  1. 100
  2. 80
  3. 90
  4. 70

Answer (Detailed Solution Below)

Option 2 : 80

Bar Graph and Line Graph Question 1 Detailed Solution

Concept used:

Average = Total women / Number of cities

Calculations:

Percent of Men who have BMW car in Jaipur = 70%

⇒ Percent of Women who have BMW car in Jaipur = (100 - 70)% = 30%

Number of Women who have BMW in Jaipur = 200 × 30 / 100 = 60

Percent of Women who have BMW car in Delhi = 20%

Number of Women who have BMW in Delhi = 175 × 20 / 100 = 35

Percent of Women who have BMW car in Mumbai = 60%

Number of Women who have BMW in Mumbai = 275 × 60 / 100 = 165

Percent of Women who have BMW car in Udaipur = 40%

Number of Women who have BMW in Udaipur = 150 × 40 / 100 = 60

Average of Women = Total Women / Numbers of Cities

⇒ (60 + 35 + 165 + 60) / 4 = 320 / 4 = 80

The average of women who have BMW cars in all the cities is 80

Bar Graph and Line Graph Question 2:

In this bar graph represent the total number of vacant seats in SSC and Bank.

F1 Mamata SSC 16.09.22  G20

What is the percentage of SSC vacant seats out of total vacant seats in these five years?

  1. 50%
  2. 55%
  3. 60%
  4. 65%

Answer (Detailed Solution Below)

Option 2 : 55%

Bar Graph and Line Graph Question 2 Detailed Solution

Given:

Total Vacant seats in SSC and Bank in five years.

Calculation:

Total Vacant seats in SSC in this five years = 750 +900 + 700 + 800 + 640

⇒ 3790

Total Vacant seats in Bank in this five years = 480 + 500 + 750 + 820 +550

⇒ 3100

Total Vacant seats in Bank and SSC in this five year = 3790 + 3100 = 6890

Percentage of SSC = (3790 × 100) / 6890

⇒ 55 %

Percentage of Vacant seats in SSC in this five years = 55 %

Bar Graph and Line Graph Question 3:

Study the following percentage graph and answer the question, 

Total Expenditure of the company = 100,000

F5 Savita SSC 25-7-24 D1 V2

 

The Total Expenditure of the company is how many times of its total expenditure of Research and Salary?

  1. 3 times 
  2. 7 times 
  3. 4 times 
  4. 6 times 

Answer (Detailed Solution Below)

Option 3 : 4 times 

Bar Graph and Line Graph Question 3 Detailed Solution

Given:

Total Expenditure of the company = 100,000

Solution:

Total Expenditure of Research = 100,000 × 5%

⇒ 5000

Total Expenditure of Salary = 100,000 × 20%

⇒  20000

Total Expenditure of Research and Salary = 5000 + 20000

⇒ 25000

Total Expenditure of The company = 100,000 

⇒ Total expenditure of the company / Total expenditure of Research and Salary

⇒ 100,000 / 25000 = 4

Total Expenditure of the company is 4 times of its total expenditure of Research and Salary.

Bar Graph and Line Graph Question 4:

 Data of students (in Percentage) Who get Admission after Matriculation.

F1 Revannath SSC 21.10.2022 G4

If the Total number of Students in a School is 280. What is The Difference between Arts students and Commerce students?

  1. 112
  2. 115
  3. 120
  4. 128

Answer (Detailed Solution Below)

Option 1 : 112

Bar Graph and Line Graph Question 4 Detailed Solution

Given:

The Total number of a Student of a school is 280.

Solution:

The number of students in Arts = 55% of 280

 ⇒ 154

The number of students in Commerce = 15% of 280

⇒ 42

Difference between Arts students and Commerce students = 154 - 42

⇒ 112

Difference between Arts students and Commerce students = 112

Bar Graph and Line Graph Question 5:

Comprehension:

Directions: Study the given graphs and answer the question that follows.

The graphs show total number of students and number of boys(%) in five schools A, B, C, D and E.

graph 1

graph 2

The total number of girls in school B is x and the total number of boys in school D is y. Which of the following option is correct?

  1. x = 189, y = 376
  2. x = 189, y = 378
  3. x = 378, y = 189
  4. x = 185, y = 375

Answer (Detailed Solution Below)

Option 2 : x = 189, y = 378

Bar Graph and Line Graph Question 5 Detailed Solution

Given:

Schools

Total students

Boys

A

400

33%

B

420

55%

C

520

35%

D

630

60%

E

440

50%

 

Calculations:

Schools

Total students

Boys

Girls

A

400

33%

(100% – 33%) = 67%

B

420

55%

(100% – 55%) = 45%

C

520

35%

(100% – 35%) = 65%

D

630

60%

(100% – 60%) = 40%

E

440

50%

(100% – 50%) = 50%

 

The total number of girls in school B is x = 45% of 420 = 189

The total number of boys in school D is y = 60% of 630 = 378

x = 189, y = 378.

Bar Graph and Line Graph Question 6:

Data Show the % of different sect of  Christian Population.

F1 Revannath SSC 21.10.2022 G7

If The total population of Christian is 2,18,000. Find out the number of Orthodox in Christian?

  1. 26180
  2. 26150
  3. 26160
  4. 26170

Answer (Detailed Solution Below)

Option 3 : 26160

Bar Graph and Line Graph Question 6 Detailed Solution

Given:

Total number of Christian = 2,18,000

Solution:

The % of Orthodox in Christian = 12%

Total number of Christian (100%) = 2,18,000

Total number of Orthodox in Christian = (2,18,000 / 100) × 12

 ⇒ 26160

Total number of Orthodox in Christian = 26,160

Bar Graph and Line Graph Question 7:

Comprehension:

Instructions: Study the graph below and answer the question based on it.

The number of vehicles manufactured by the company X and Y from 2001 to 2006 has been given (in thousands). 

SSC Himanshu Akash 02.04.2024 G3

What is the difference between the number of vehicles produced by Company X in the year 2001 and 2002? (In thousand)

  1. 5
  2. 3
  3. 6
  4. 4

Answer (Detailed Solution Below)

Option 4 : 4

Bar Graph and Line Graph Question 7 Detailed Solution

Calculation:

⇒ Number of vehicles produced by Company X in 2001 = 57

⇒ Number of vehicles produced by Company X in 2002 = 61

⇒ Difference = 61 - 57 = 4

∴ The correct answer is Option 4).

Bar Graph and Line Graph Question 8:

Comprehension:

Direction: Read the following Bar graph carefully and answer the following questions

The Bar graph shows the number of BMW and Audi cars in 4 different cities.

Banking Akash gautam 26.05.2023 G3

The Line graph shows the Percent of men and women who have car in 4 different cities.

Banking Akash gautam 26.05.2023 G2

Find the degree value of all men who have BMW cars in all cites with respect to total number of cars in all four cities.

  1. 120°
  2. 100°
  3. 108°
  4. 110°
  5. None of these

Answer (Detailed Solution Below)

Option 3 : 108°

Bar Graph and Line Graph Question 8 Detailed Solution

Concept used:

Degree = (Total Men who have BMW / Total number of cars) × 360°

Calculations:

Number of men who have BMW in Jaipur = 200 × (70 / 100) = 140

Number of men who have BMW in Delhi = 175 × (80 / 100) = 140

Number of men who have BMW in Mumbai = 275 × (40 / 100) = 110

Number of men who have BMW in Udaipur = 150 × (60 / 100) = 90

Total number of men who have BMW cars in all the cities = 140 + 140 + 110 + 90 = 480

Total number of cars in all the cities = 200 + 125 + 175 + 250 + 275 + 300 + 150 + 125 = 1600

Degree value of men who have BMW cars = (Total Men who have BMW / Total number of cars) × 360°

⇒ (480 / 1600) × 360° = 108°

∴ The degree value of men who have BMW cars is 108°

Bar Graph and Line Graph Question 9:

Comprehension:

Direction: Read the following Bar graph carefully and answer the following questions

The Bar graph shows the number of BMW and Audi cars in 4 different cities.

F1 Sanyukta Others 26.5.22 G1

The Line graph shows the Percent of men and women who have car in 4 different cities.

Banking Akash gautam 26.05.2023 G2

Find the ratio of men who have BMW car with the women who have Audi car in all four cities.

  1. 20 : 19
  2. 24 : 19
  3. 24 : 29
  4. 20 : 29

Answer (Detailed Solution Below)

Option 2 : 24 : 19

Bar Graph and Line Graph Question 9 Detailed Solution

Calculations:

Number of men who have BMW in Jaipur = 200 × (70 / 100) = 140

Number of men who have BMW in Delhi = 175 × (80 / 100) = 140

Number of men who have BMW in Mumbai = 275 × (40 / 100) = 110

Number of men who have BMW in Udaipur = 150 × (60 / 100) = 90

Total number of men who have BMW call in all the cities = 140 + 140 + 110 + 90 = 480

Number of Women who have Audi in Jaipur = 125 × 40 / 100 = 50

Number of Women who have Audi in Delhi = 250 × 20 / 100 = 50

Number of Women who have Audi in Mumbai = 300 × 60 / 100 = 180

Number of Women who have Audi in Udaipur = 125 × 80 / 100 = 100

Total Number of Women who have Audi cars in four cities = 50 + 50 + 180 + 100 = 380

Hence ratio of men who have BMW car with the women who have Audi car in all four

⇒ 480 ∶ 380

⇒ 24 ∶ 19

Bar Graph and Line Graph Question 10:

Comprehension:

Directions: Study the given graphs and answer the question that follows.

The graphs show total number of students and number of boys(%) in five schools A, B, C, D and E.

graph 1

graph 2

Find the difference between the number of boys in school B and the number of boys in school D.

  1. 174
  2. 157
  3. 147
  4. 175

Answer (Detailed Solution Below)

Option 3 : 147

Bar Graph and Line Graph Question 10 Detailed Solution

Given:

Schools

Total students

Boys

A

400

33%

B

420

55%

C

520

35%

D

630

60%

E

440

50%

 

Calculation:

Number of boys in school B = 55% of 420 = 231

Number of boys in school D = 60% of 630 = 378

Required difference = 378 - 231 = 147

∴ 147

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