Number Arrangement MCQ Quiz - Objective Question with Answer for Number Arrangement - Download Free PDF

Given:

9 5 1 9 7 9 4 5 7 6 8 2 9 7 7 2 9 5 8 5 6 7 3 8 6 9 7

Condition to be checked:

Even ⇒ Odd ⇒ Even

9 5 1 9 7 9 4 5 7 6 8 2 9 7 7 2 9 5 8 5 6 7 3 8 6 9 7

Thus, there is 1 such odd number in the sequence (8 5 6)

Hence, the correct option is "Option 1".

Given:

9 4 6 9 1 1 6 8 8 7 7 6 7 6 8 5 8 8 1 6 2 1 9 3 2 2 2

Condition to be checked:

Odd ⇒ Odd ⇒ Even

9 4 6 9 1 1 6 8 8 7 7 6 7 6 8 5 8 8 1 6 2 1 9 3 2 2 2

Thus, there are 3 such odd numbers in the sequence (1 1 6, 7 7 6, 9 3 2)

Hence, the correct option is "Option 1".

Given series: 7 6 9 8 6 5 6 6 7 1 6 5 6 9 5 6 4 9 6 5 6 7 6 7

According to the question, 6s which are neither immediately preceded by 5 nor immediately followed by 7:

Required condition: Not 5 - 6 - Not 7

7 6 9 8 6 5 6 6 7 1 6 5 6 9 5 6 4 9 6 5 6 7 6 7

Thus, there are four such 6s which are neither immediately preceded by 5 nor immediately followed by 7.

Hence, "Option 4" is the correct answer.

Given series: 5 1 4 7 3 9 8 5 7 2 6 3 4 5 8 6 3 5 2 4 3 4 9 6

According to the question, such odd numbers which are immediately preceded by an even number:

Required condition: Even number - Odd number

5 1 4 7 3 9 8 5 7 2 6 3 4 5 8 6 3 5 2 4 3 4 9 6

Thus, there are seven such odd numbers which are immediately preceded by an even number.

Hence, "Option 3" is the correct answer.

Given series: 2 5 6 3 4 7 8 6 4 2 4 6 2 5 8 6 2 3 5 8 6 8 6 1

According to the question, such 6s which are exactly divisible by its immediate succeeding number:

Required condition: 6 - Factor of 6

2 5 6 3 4 7 8 6 4 2 4 6 2 5 8 6 2 3 5 8 6 8 6 1

Thus, there are four such 6s which are exactly divisible by its immediate succeeding number.

Hence, "Option 4" is the correct answer.

Second element in every pair is third to the right of first element except 27.

6 6 8 5 5 3 7 3 7 2 5 9 8 7 8 1 5 5 4

There is a gap of two digits in every number like, there are 5 and 5 between 8 and 3 in 83.

Similarly, there are 7 and 2 between 3 and 5 in 35 and 7 and 8 between 8 and 1 in 81. But there are 5, 8, 8, and 7 between 2 and 7 in 27.

Hence, 27 does not belong to the group.

According to the given condition the series becomes:

Now we have, 2 as third from left and 8 as second from right.

Sum = 2 + 8 = 10

Hence, the correct answer is option 1).

Given numbers: 378 256 431 875 762

On subtracting first and third digits,

378 = 8 – 3 = 5

256 = 6 – 2 = 4

431 = 4 – 1 = 3

875 = 8 – 5 = 3

762 = 7 – 2 = 5

According to the given information:
When 2 is added to each odd digit and 1 is subtracted from each even digit in the number 94387251,
           

Now the new number is: 113579173

Now, the sum of the first, fifth and last digit is,
1 + 7 + 3 = 11

Hence the correct answer is option 3)

The logic followed here is:

Condition to be checked:

i) The number 8 not followed by the number 4 but is preceded by the number 5 are given below:-

5 → 8 → Not 4 (4)

6 5 8 2 3 5 8 1 2 5 8 3 4 3 5 6 5 4 5 8 6 5 8 4 5 8

So, there are 5 pairs in which the number 8 is not followed by the number 4 but is preceded by the number 5.

Hence, "option 1" is the correct answer.

Mistake Points 

Immediately preceded by means immediately before or to come just before.

Immediately followed by means immediately after or to come just after.

Given: 5442673314884743581

The number of 4s that are completely divisible by the number on their right but not divisible by the number on their left is:

Note: other 4s are not counted because

Hence, the correct answer is "1".

Given number is: 56789

After 1 is added to every odd digit and 1 is subtracted from every even digit as per the question the number become: 658710

Numbers that are not divisible by 2 are odd numbers.

Given sequence of numbers is :

5 1 4 7 3 9 8 5 7 2 6 3 1 5 8 6 3 8 5 2 2 4 3 4 9 6 

(5,1) (7,3) (3,9) (5,7) (3,1) (1,5)

Hence, 6 is the correct answer.

Left 5 9 7 6 8 9 5 6 9 5 7 8 4 6 9 3 5 8 8 6 7 7 9 Right

odd numbers each of which is an odd number after and before the odd number is; 

5 9 7 6 8 9 5 6 9 5 7 8 4 6 9 3 5 8 8 6 7 7 9

There are four odd numbers that are after and before the odd number.

Hence, "Four" is the correct answer.