Mixed Series MCQ Quiz - Objective Question with Answer for Mixed Series - Download Free PDF

Given series:

(Left) # % 5 4 3 2 1 @ % * # * 6 § 9 8 % $ 1 5 6 4 2 (Right)

Condition to be checked:

How many such numbers are there each of which is immediately preceded by a symbol and also immediately followed by another symbol.

Symbol → Number → Symbol

Let's examine the series from left to right:

(Left) # % 5 4 3 2 1 @ % * # * 6 § 9 8 % $ 1 5 6 4 2 (Right)

So, one number are there which is immediately preceded by a symbol and also immediately followed by another symbol

Hence, the correct answer is "Option 2".

Given series:

(Left) & 6 @ 3 Ω 9 # £ 8 $ % 4 5 7 & 1 * 2 (Right)

Condition to be checked:

How many such numbers are there, each of which is immediately preceded by a symbol and also immediately followed by a number?

Symbol → Number → Number

Let's examine the series:

(Left) & 6 @ 3 Ω 9 # £ 8 $ % 4 5 7 & 1 * 2 (Right)

The numbers that are immediately preceded by a symbol and immediately followed by a number are:

4 (preceded by % and followed by 5)

Thus there is only one such number (4) that follows the given conditions.

Hence, "Option 1" is the correct answer.

The logic followed is:

Given series: 

Ω 9 2 # 1 8 $ 7 3 6 * £ + 5 4 @ % &

Condition to be checked:

Numbers that are immediately preceded by a symbol and immediately followed by another symbol.

Symbol → Number → Symbol

Analyzing the series:

Ω 9 2 # 1 8 $ 7 3 6 * £ + 5 4 @ % &

Thus, in the given series given condition is not satisfied. 

Hence, the correct answer is option 4.

Given: (Left) Ω 9 % 3 1 * £ 5 4 2 & 6 # @ 8 $ 7 + (Right)

Here, We need to find the symbols are there each of which is immediately preceded by another symbol and also immediately followed by a number

Required pattern: symbol - Symbol - Number

(Left) Ω 9 % 3 1 * £ 5 4 2 & 6 # @ 8 $ 7 + (Right)

So, there is two such pair in the series '* £ 5', '# @ 8'.

Hence, the correct answer is "Option 1".

Given series:

# 1 * £ 3 6 & @ 8 $ 7 + 5 4 2 Ω 9 %

Condition to be checked:

A symbol which is immediately preceded by a number and also immediately followed by another symbol.

Number → Symbol → Symbol

# 1 * £ 3 6 & @ 8 $ 7 + 5 4 2 Ω 9 %

There is two such symbol which is immediately preceded by a number and also immediately followed by another symbol.

Hence, "Option 2" is the correct answer.

Consider the following series: _____

S 4 5 4 S S 4 5 4 S 7 S W 7 5 7 5 W 4 4 4 W C C 5 5 7 C C 7

Numbers are 454, 454, 757, 575, 444

The given series can be represented as:

So, there are 2 symbols: & and # in the series which are between the seventh element from the right end and the fifth element from the left end of the given series.

Hence, the correct answer is '2'.

• '3' is the 10^th element from the right end.

• '+' is the 7^th element to the right of '3'.

Hence, 'option 4' is the correct answer.

 7th to the right of the 10th element from the right end = 10 - 7 = 3rd element from the right end = +

Given arrangement: T 5 S # R 2 1 * A & Z 7 C ? 4 P 6 E 8 K Y @ 3 F $

If every symbol is deleted from the arrangement, we have:

T 5 S R 2 1 A Z 7 C 4 P 6 E 8 K Y 3 F

8^th to the right of the 15^th element from the right end = 15 – 8 = 7^th from the right end.

7^th from the right end is 6.

Given series: 3R # 2 A S K 5 % T 7 & N Y + X B / L Q @ 1

If the first half of the above series is reversed then:-

7 T % 5 K S A 2 # R 3 & N Y + X B / L Q @ 1

• 18th term from the right end = K
  • 7 T % 5 K S A 2 # R 3 & N Y + X B / L Q @ 1
• 15th term to the right of K = Q
  • 7 T % 5 K S A 2 # R 3 & N Y + X B / L Q @ 1

Hence, "Q" is the correct answer. 

According to the given information,

Number should come before a letter , but not after a symbol.

Not symbol → Number → Letter

P n 4 # 3 a 2 Q r 6 4 N d $ e # f 6 g 9 h u z 7 c h I $ 5 x u 4 #

Number of times the condition satisfied is :

[a 2 Q] , [6 4 N] , [f 6 g] , [g 9 h] , [z 7 c]

Required series: 1%MB#6&NC=3!O

Removing every alternate letter or number or symbol:- 1 M # & C 3 O

5^th term from right is “#”.

Hence, “#” is the correct answer.

Given series:-

3 R # 2 A $ K 5 % T 7 & N Y ÷ X B / L Q @ 1

Second half: & N Y ÷ X B / L Q @ 1

The second half of the above series is reversed, then the new series is:-

3 R # 2 A $ K 5 % T 7 1 @ Q L / B X ÷ Y N &

From the above series:-

Similarly,

Hence, "option 2" is the correct answer.

Consider the given series:

S 4 5 4 S S 4 5 4 S 7 S W 7 5 7 5 W 4 4 4 W C C 5 5 7 C C 7

Hence, five numbers are there which are immediately preceded by 5:- 54, 54, 57, 55, 57

The given series: 3 X ! I B O # F 4 5 * 1 K 2 $ 8 R 8 % Z

If we drop all the special characters from the series, we get:

3 X I B O F 4 5 1 K 2 8 R 8 Z

Hence, "8" is the 10th term to the right of 'X'.