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Integer Property |
Addition |
Multiplication |
Subtraction |
Division |
Closure Property |
a + b ∈ Z |
a × b ∈ Z |
a – b ∈ Z |
a ÷ b ∉ Z |
Commutative Property |
a + b = b+ a |
a × b = b × a |
a – b ≠ b – a |
a ÷ b ≠ b ÷ a |
Associative Property |
a + (b + c) = (a + b) + c |
a × (b × c) = (a × b) × c |
(a – b) – c ≠ a – (b – c) |
(a ÷ b) ÷ c ≠ a ÷ (b ÷ c) |
Identity Property |
a + 0 = a = 0 + a |
a × 1 = a = 1 × a |
a – 0 = a ≠ 0 – a |
a ÷ 1 = a ≠ 1 ÷ a |
Distributive Property |
a × (b + c) = a × b + a × c a × (b − c) = a × b − a × c |
Division of Integers: The division of two integers is always an integer. If a and b are any two integers, then a/b = is also an integer. Example: 4/2 = 2.
The commutative property is a math rule that says that the order in which we add, multiply, subtract or divide the numbers does not change the product.
This law simply states that with addition and multiplication of numbers, you can change the grouping of the numbers in the problem and it will not affect the answer.
An identity is a number that when added, subtracted, multiplied or divided with any number (let’s call this number n), allows n to remain the same. This is also a property of whole numbers
Distributive Property is used to solve expressions easily by distributing a number to the numbers given in brackets.
Integers are whole numbers that can be positive, negative, or zero. They can be divided into three main types based on how they behave when divided by each other.
Positive ÷ Positive = Positive
When you divide a positive number by another positive number, the result is always positive.
Example: 6 ÷ 3 = 2
Negative ÷ Negative = Positive
If you divide a negative number by another negative number, the result is positive as well.
Example: -6 ÷ -3 = 2
Positive ÷ Negative = Negative
When you divide a positive number by a negative number, or a negative number by a positive number, the result is always negative.
Example:
6 ÷ -3 = -2
or
-6 ÷ 3 = -2
Let’s see some examples of Properties of Integers that come in exams.
Solved Example 1: Find two consecutive integers whose sum is equal 129.
Solution: Let x and x + 1 (consecutive integers differ by 1) be the two numbers. Use the fact that their sum is equal to 129 to write the equation.
x + (x + 1) = 129
Solve for x to obtain
x = 64
The two numbers are
x = 64 and x + 1 = 65
We can see that the sum of the two numbers is 129.
Solved Example 2: The sum of three consecutive even integers is equal to 84. Find the numbers.
Solution: The difference between two even integers is equal to 2. Let x, x + 2 and x + 4 be the three numbers. Their sum is equal to 84, hence
x + (x + 2) + (x + 4) = 84
Solve for x and find the three numbers
x = 26 , x + 2 = 28 and x + 4 = 30
The three numbers are even. Check that their sum is equal to 84.
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