Question
Download Solution PDFWhich of the following is the correct output for the ‘C’ program given below:
#include<stdio.h>
void afun(char *) ;
int main( )
{
char ch[10] ;
ch[0] = 'X' ; ch[1] = 'Y' ; ch[2] = 'Z' ;
ch[3] = 'Z' ;
afun (& ch[0]) ;
return 0 ;
}
void afun (char *c)
{
c++ ;
printf("%c", *c) ;
c++ ;
printf("%c\n", *c) ;
}
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDF|
Assume Decimal address |
100 |
101 |
102 |
103 |
104 |
105 |
106 |
107 |
108 |
109 |
|
character array |
ch[0] |
ch[1] |
ch[2] |
ch[3] |
ch[4] |
ch[5] |
ch[6] |
ch[7] |
ch[8] |
ch[9] |
|
corresponding value |
X |
Y |
Z |
Z |
\0 |
|
|
|
|
|
&ch[0] → gives that address of first element
int *c = 100
c++ \\ c = c + 1 = 100 + 1 = 101
printf(“%c”,*c) \\ dereferencing the value at location 101
output = Y
c++ \\ c = c + 1 = 101 + 1 = 102
printf(“%c”,*c) \\ dereferencing the value at location 102
output = Z
Final Output: YZ
Last updated on Jun 12, 2025
-> The UGC NET June 2025 exam will be conducted from 25th to 29th June 2025.
-> The UGC-NET exam takes place for 85 subjects, to determine the eligibility for 'Junior Research Fellowship’ and ‘Assistant Professor’ posts, as well as for PhD. admissions.
-> The exam is conducted bi-annually - in June and December cycles.
-> The exam comprises two papers - Paper I and Paper II. Paper I consists of 50 questions and Paper II consists of 100 questions.
-> The candidates who are preparing for the exam can check the UGC NET Previous Year Papers and UGC NET Test Series to boost their preparations.