Which of the following interchanges of numbers and mathematical signs would make the given equation correct?

729 × 81 ÷ 20 + 16 − 6 = 50

This question was previously asked in
SSC CGL 2022 Tier-I Official Paper (Held On : 01 Dec 2022 Shift 4)
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  1. 6 and 20, × and ÷
  2. 20 and 50, + and − 
  3.  16 and 50, × and +
  4. 16 and 20, + and ÷

Answer (Detailed Solution Below)

Option 1 : 6 and 20, × and ÷
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Detailed Solution

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The correct pattern followed here is:

Solve with the help of the BODMAS Rule:

Given: 729 × 81 ÷ 20 + 16 − 6 = 50

Option 1) 6 and 20, × and ÷ 

After replacing the sign and number we get the:

⇒ 729 ÷ 81 × 6 + 16 − 20 = 50

9 × 6 + 16 − 20 = 50

54 + 16 - 20 = 50

⇒ 70 - 20 = 50

⇒ 50 = 50

⇒ LHS = RHS

Option 2)  20 and 50, + and − 

After replacing the sign and number we get the:

⇒ 729 × 81 ÷ 50 - 16 + 6 = 20

729 × 1.62 - 16 + 6 = 20

1180.98 - 16 + 6 = 20

⇒ 1186.98 - 16 = 20

⇒ 1170.98 ≠ 20

⇒ LHS ≠ RHS

Option 3) 16 and 50, × and +

After replacing the sign and number we get the:

⇒ 729 + 81 ÷ 20 × 50 − 6 = 16

⇒ 729 + 1.62 × 50 - 6 = 16

729 + 81 - 6 = 16

⇒ 810 - 6 = 16

⇒ 804 ≠ 16

⇒ LHS ≠ RHS

Option 4) 16 and 20, + and ÷

⇒ 729 × 81 + 16 ÷ 20 − 6 = 50 

729 × 81 + 0.8 - 6 = 50

59049 + 0.8 - 6 = 50

⇒ 59049.8 - 6 = 50

⇒ 59043.8 ≠ 50

⇒ LHS ≠ RHS

Hence, the correct answer is "Option 1".

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