What will\(\rm \sqrt{\frac{1+\sin \theta}{1-\sin \theta}}\)  be equal to?

Calculation:

\(\rm √{\frac{1+\sin θ}{1-\sin θ}}\) = \(\rm √{\frac{(1+\sin θ)(1+\sin θ)}{(1-\sin θ) (1+\sin θ)}}\) 

⇒ \(\rm √{\frac{(1+\sin θ)^2}{(1-\sin^2 θ) }}\) = √ (1 + sin²θ + 2sinθ/ cos²θ)

⇒ sec²θ + tan²θ + 2tanθsecθ

⇒ √((secθ + tanθ)²) = secθ + tanθ 

Hence, The Correct Answer is secθ + tanθ.