What is the resultant resistance of 3 Ω and 6 Ω resistances connected in series?

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RRB JE Previous Paper 2 (Held On: 23 May 2019 Shift 1)
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  1. 2 Ω
  2. 9 Ω
  3. 16 Ω
  4. 12 Ω

Answer (Detailed Solution Below)

Option 2 : 9 Ω
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CONCEPT:

  • Resistances in series combination: When two or more resistances are connected one after another such that the same current flows through them are called as resistances in series.

F1 Jitendra Deepak 30.03.2020 D7

  • The net resistance/equivalent resistance (R) of resistances in series is given by:
  • Equivalent resistance, 

R = R1 + R2      ...(1)

CALCULATION:

Given that: R1 = 3 Ω  and R2 = 6 Ω 

Using equation 1,

⇒ R = 3 + 6 = 9 Ω 

EXTRA POINTS:

  • Resistances in parallel combination: When the terminals of two or more resistances are connected at the same two points and the potential difference across them is equal is called resistances in parallel.

F1 Jitendra Deepak 30.03.2020 D8

  • The net resistance/equivalent resistance(R) of resistances in parallel is given by:

\(\frac{1}{R} = \frac{1}{{{R_1}}} + \frac{1}{{{R_2}}}\)

  • Equivalent resistance decreases in the case of a parallel combination.
  • In series combinations, the current remains constant while in case of parallel combination, the potential difference remains constant.
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