What is the peak to peak voltage of 250 V AC?

Question

Question

This question was previously asked in

ISRO (VSSC) Technician Electrician 2019 Official Paper

Answer 1

Concept:

For a sinusoidal alternating waveform

Peak to peak value of voltage (V_p-p) = 2 (Peak value)
The peak value of voltage (V_p) = √2 V_rms
RMS value of voltage \(\left( {{V_{rms}}} \right) = \frac{{{V_p}}}{{\surd 2}}\)
The average value of voltage \(\left( {{V_{avg}}} \right) = \frac{{2{V_p}}}{\pi }\)

Calculation:

V_rms = 250 V

V_p= √2 × 250 V

V_p-p= 2 × √2 × 250

∴ V_p-p= 707 V