Two pi and half sigma bonds are present in -

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  1. O2
  2. O2+
  3. N2+
  4. N2

Answer (Detailed Solution Below)

Option 3 : N2+
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CONCEPT:

Molecular Orbital Theory

  • Molecular Orbital Theory (MOT) describes bonding in terms of molecular orbitals, which are formed by the combination of atomic orbitals.
  • Bonds in diatomic molecules like \( {O}_2 , {O}_2^+ , {N}_2 , and \ \ {N}_2^+\) can be analyzed using this theory.
  • Molecular orbitals are filled according to energy levels: first bonding molecular orbitals, then antibonding ones.

EXPLANATION:

  • O2:
    • Electronic configuration is \((1s\sigma_{g})^2 (1s\sigma_{u}^*)^2 (2s\sigma_{g})^2 (2s\sigma_{u}^*)^2 (2p\sigma_{g})^2 (2pπ_u)^4 (2pπ_g^*)^2\)
    • Total bond order: 2 (from MOT theory:1/2(10 - 6) = 2 )
    • Contains one sigma -bond and one π  -bonds.
  • O2+:
    • Electronic configuration is \((1s\sigma_{g})^2 (1s\sigma_{u}^*)^2 (2s\sigma_{g})^2 (2s\sigma_{u}^*)^2 (2p\sigma_{g})^2 (2pπ_u)^4 (2pπ_g^*)^1\)
    • Total bond order: 1.5 (from MOT theory:1/2(9 - 6) = 1.5 )
    • Contains one sigma -bond, one π -bonds, and a half sigma* -bond due to the unpaired electron.
  • N2+:
    • Electronic configuration is \((1s\sigma_{g})^2 (1s\sigma_{u}^*)^2 (2s\sigma_{g})^2 (2s\sigma_{u}^*)^2 (2p\sigma_{g})^2 (2pπ_u)^4 (2pπ_g^*)^1\)
    • Total bond order: 2.5 (from MOT theory: 1/2(10 - 5) = 2.5 )
    • Contains one sigma -bond, two π  -bonds, and a half sigma* -bond due to the unpaired electron.
  • N2:
    • Electronic configuration is \((1s\sigma_{g})^2 (1s\sigma_{u}^*)^2 (2s\sigma_{g})^2 (2s\sigma_{u}^*)^2 (2p\sigma_{g})^2 (2pπ_u)^4\)
    • Total bond order: 3 (from MOT theory: 1/2(10 - 4) = 3 )
    • Contains one sigma -bond and two pi -bonds.

Among these molecules,  N2+ contains 2 pi bonds and half a sigma bond.

The correct option is N2+

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