Question
Download Solution PDFTwo pi and half sigma bonds are present in -
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
Molecular Orbital Theory
- Molecular Orbital Theory (MOT) describes bonding in terms of molecular orbitals, which are formed by the combination of atomic orbitals.
- Bonds in diatomic molecules like \( {O}_2 , {O}_2^+ , {N}_2 , and \ \ {N}_2^+\) can be analyzed using this theory.
- Molecular orbitals are filled according to energy levels: first bonding molecular orbitals, then antibonding ones.
EXPLANATION:
- O2:
- Electronic configuration is \((1s\sigma_{g})^2 (1s\sigma_{u}^*)^2 (2s\sigma_{g})^2 (2s\sigma_{u}^*)^2 (2p\sigma_{g})^2 (2pπ_u)^4 (2pπ_g^*)^2\)
- Total bond order: 2 (from MOT theory:1/2(10 - 6) = 2 )
- Contains one sigma -bond and one π -bonds.
- O2+:
- Electronic configuration is \((1s\sigma_{g})^2 (1s\sigma_{u}^*)^2 (2s\sigma_{g})^2 (2s\sigma_{u}^*)^2 (2p\sigma_{g})^2 (2pπ_u)^4 (2pπ_g^*)^1\)
- Total bond order: 1.5 (from MOT theory:1/2(9 - 6) = 1.5 )
- Contains one sigma -bond, one π -bonds, and a half sigma* -bond due to the unpaired electron.
- N2+:
- Electronic configuration is \((1s\sigma_{g})^2 (1s\sigma_{u}^*)^2 (2s\sigma_{g})^2 (2s\sigma_{u}^*)^2 (2p\sigma_{g})^2 (2pπ_u)^4 (2pπ_g^*)^1\)
- Total bond order: 2.5 (from MOT theory: 1/2(10 - 5) = 2.5 )
- Contains one sigma -bond, two π -bonds, and a half sigma* -bond due to the unpaired electron.
- N2:
- Electronic configuration is \((1s\sigma_{g})^2 (1s\sigma_{u}^*)^2 (2s\sigma_{g})^2 (2s\sigma_{u}^*)^2 (2p\sigma_{g})^2 (2pπ_u)^4\)
- Total bond order: 3 (from MOT theory: 1/2(10 - 4) = 3 )
- Contains one sigma -bond and two pi -bonds.
Among these molecules, N2+ contains 2 pi bonds and half a sigma bond.
The correct option is N2+
Last updated on May 30, 2025
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