Question
Download Solution PDFThe value of \(\rm \frac{sin\space23°}{cos\space67°}+\frac{cos\space71°}{sin\space19°}\) is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
\(\rm \frac{sin\space23°}{cos\space67°}+\frac{cos\space71°}{sin\space19°}\)
Formula used:
sin (90°- x) = cos x
cos (90°- x) = sin x
Calculation:
\(\rm \frac{sin\space23°}{cos\space67°}+\frac{cos\space71°}{sin\space19°}\)
⇒ sin(90° - 67°)/cos 67° + cos (90° - 19°)/sin 19°
⇒ cos 67°/ cos 67° + sin 19°/sin 19°
⇒ 1 + 1 = 2
∴ The required result = 2
Last updated on Jul 1, 2025
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