The term symbol for the ground dinitrogen cation radical (\(N^+_2\)) is

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CSIR-UGC (NET) Chemical Science: Held on (26 Nov 2020)
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  1. 2u
  2. 2\({\sum\nolimits_u^ - {} }\)
  3. 2g
  4. 2\({\sum\nolimits_g^ + {} }\)

Answer (Detailed Solution Below)

Option 4 : 2\({\sum\nolimits_g^ + {} }\)
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Concept:

  • The term symbol describes the (total) angular momentum quantum numbers in a multi-electron atom.
  • Each energy level of an atom with a given electron configuration is described by not only the electron configuration but also its own term symbol, as the energy level also depends on the total angular momentum including spin.
  • The molecular term symbol is represented by

\(^{2S + 1}\Lambda _{(g/u)}^{( + / - )}\)

where S is the total spin quantum number, and it is given by

\({n \over 2}\), where n is number of unpaired electrons

\(\Lambda \) is the projection of the orbital angular momentum along the internuclear axis,

(g/u) represents the symmetry or parity with respect to inversion (i) through a center of symmetry,
(+/-) is the reflection symmetry along an arbitrary plane containing the internuclear axis.

Explanation:

  • N2+ contains a total of 13 electrons and the electronic configuration of N2+ is \(1\sigma _g^21{\sigma ^ * }_u^22\sigma _g^22{\sigma ^ * }_u^21\pi _u^43\sigma _g^1\)
  • The number of unpaired electron in N2+ is 1, and it is present in a \(\sigma \) orbital.  
  • The total spin quantum number (S) for N2+ is \({1 \over 2}\), and the value of 2S+1 is,

\(2 \times {1 \over 2} + 1\)

 \( = 2\)

  • The value of \(\Lambda \) for a \(\sigma \) orbital is 0, and it is coded by \({\sum\nolimits }\)
  • As the symmetry of the  \(\sigma \) orbital is gerade, it is represented as g.
  • The  \(\sigma \) orbital is symmetrical with respect to the reflection symmetry, thus it will be represented by a +ve sign.
  • Thus, the molecular term symbol is \(^2\sum _g^ + \)    

Conclusion:

  • Hence, the term symbol for the ground dinitrogen cation radical (\(N^+_2\)) is \(^2\sum _g^ + \)  
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