Question
Download Solution PDFThe sum of the first 18 terms of the series 3, 6, 9, 12, 15, ....... is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Sum of consecutive numbers from 1 to n: \(\rm1 + 2 + 3 +\ ...\ + n = \dfrac{n(n+1)}{2}\).
Calculation:
The sum of the first 18 terms of the given series can be written as:
3 + 6 + 9 + 12 + 15, .......
⇒ 3(1 + 2 + 3 + 4 + 5 + ....)
⇒ \(\frac{3 \times 18 \times 19}{2} = 513\)
Last updated on May 31, 2025
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