\(\sqrt2,\sqrt8,\sqrt{18},\sqrt{32}\)....is An A.P. series. Find the common difference,

Question

Question

This question was previously asked in

NPCIL Assistant Grade-1 (HR/F&A/C&MM/Steno Grade-I) Official Paper-II (Held In: 2022)

Answer 1

Given:

√2, √8, √(18), √(32).... is an A.P. series.

Formula used:

For an A.P. series, the common difference (d) is given by:

d = a_n - a_n-1

Calculations:

First term (a₁) = √2

Second term (a₂) = √8

Third term (a₃) = √18

Fourth term (a₄) = √32

To find the common difference (d):

d = a₂ - a₁

⇒ d = √8 - √2

⇒ d = 2√2 - √2

⇒ d = (2 - 1)√2

⇒ d = 1√2

⇒ d = √2

∴ The correct answer is option (4).

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