Question
Download Solution PDFThe refractive indices of quartz crystal for right handed and left handed circularly polarized light of wavelength 762.9 nm are 1.5391 and 1.5392 respectively. The angle of rotation produced by the crystal plate of thickness 0.5 mm is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Angle of rotation:
If µR ,µL be the refractive indices of quartz crystal for right handed and left handed vibrations respectively (µL > µR ) then optical path difference on passing through a quartz crystal slab of thickness ‘t’ is given as,
Path difference = (µL - µR) t
If λ be the wavelength of light used, then phase difference will be
\(\delta = \frac {2π}{λ} ({μ_L}-{μ_R}) t\)
Angle of rotation will be
\(\frac{\delta}{2} = \frac {π}{λ} ({μ_L}-{μ_R}) t\)
Calculation:
Given μL = 1.5392; μR = 1.5391; t = 0.5 mm = 0.5 × 10-3 m; λ = 762.9 nm = 762.9 × 10-9 m;
- The angle of rotation will be
\(\frac{\delta}{2} = \frac {π}{762.9 × 10^{-9}} ({1.5392}-{1.5391}) 0.5\times 10^{-3} = 0.2058 \ radians\)
Converting radians to degrees,
Angle of rotation = 0.2058 × (180/π) = 11.79°
Last updated on Jun 19, 2025
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