The range of n-bit signed magnitude representation is

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NIMCET 2016 Official Paper
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  1. 0 to 2n - 1
  2. -(2n-1 - 1) to (2n-1 -1)
  3. -(2n-1) to (2n-1)
  4. 0 to 2n-1-1

Answer (Detailed Solution Below)

Option 2 : -(2n-1 - 1) to (2n-1 -1)
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NIMCET 2020 Official Paper
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Detailed Solution

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Concept:

In signed form, for n bits

Minimum number = –2n-1 – 1

Maximum number = 2n-1 – 1

Range is –(2n-1 – 1) to  (2n-1 – 1)

Example:

1 byte = 8 bits

Minimum number = –(2n-1 – 1) = –(28-1 – 1) = – 127

Maximum number = 2n-1 – 1 = 28-1 – 1 = 127

Additional Information

In unsigned form, for n bits

Minimum number = 0

Maximum number = 2n – 1

Range 0 to  2n – 1

In 2's complement form, for n bits

Minimum number = –2n-1

Maximum number = 2n-1 – 1

Range is –(2n-1) to  (2n-1 – 1)

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