Question
Download Solution PDFThe range of n-bit signed magnitude representation is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
In signed form, for n bits
Minimum number = –2n-1 – 1
Maximum number = 2n-1 – 1
Range is –(2n-1 – 1) to (2n-1 – 1)
Example:
1 byte = 8 bits
Minimum number = –(2n-1 – 1) = –(28-1 – 1) = – 127
Maximum number = 2n-1 – 1 = 28-1 – 1 = 127
Additional Information
In unsigned form, for n bits
Minimum number = 0
Maximum number = 2n – 1
Range 0 to 2n – 1
In 2's complement form, for n bits
Minimum number = –2n-1
Maximum number = 2n-1 – 1
Range is –(2n-1) to (2n-1 – 1)
Last updated on Jun 12, 2025
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