Question
Download Solution PDFThe output of the 4 to 1 Mux is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
In a 4 × 1 MUX
Truth-Table
|
S1 |
S0 |
V |
|
0 |
0 |
I0 |
|
0 |
1 |
I1 |
|
1 |
0 |
I2 |
|
1 |
1 |
I3 |
Y = Output = S̅1 S̅0 I0 + S̅1 S0 I1 + S1 S̅0 I2 + S1 S0 I3
MUX contains AND gate followed by OR gate
Calculation:
By re-drawing the circuit diagram
∴ I0 = 1, I1 = 0, I2 = 0, I3 = 0 & (x= S2, y = S1)
Now output of 4 × 1 MUX is
Y = F = S̅1 S̅2 I0 + S̅1 S2 I1 + S1 S̅2 I2 + S1 S2 I3
F = x̅ y̅ 1 + x̅ y 0 + x y̅ 0 + x y 0
∴ F = x̅ y̅ = \(\rm{\overline{x + y}}\)
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