The number of integer values of k, for which the equation 2sinx = 2k + 1 has a solution, is

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NDA (Held On: 18 Apr 2021) Maths Previous Year paper
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  1. zero
  2. one
  3. two
  4. four

Answer (Detailed Solution Below)

Option 3 : two
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Detailed Solution

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Concept:

The minimum and maximum value of a sin x + b cos x 

- ≤ a sin x + b cos x ≤ 

Calculation:

As we know, - ≤ a sin x + b cos x ≤ 

⇒ - ≤  2sin x + 0 cos x ≤ 

⇒ -2 ≤ 2sin x ≤ 2

⇒ -2 ≤ 2k + 1 ≤ 2

⇒ -3 ≤ 2k ≤ 1

⇒ -1.5 ≤ k ≤ 0.5

k = 0, -1 

Hence, Option 3 is correct.

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