Question
Download Solution PDFThe minimum tension reinforcement (Fe 500) in the beam of size 450 mm × 600 mm (effective depth = 550 mm) is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
As per IS 456:2000 clause 26.5.1.1, Minimum tension reinforcement (Ast) in a beam provided is given by:
\(\frac{{{A_{st}}}}{{bd}} = \frac{{0.85}}{{fy}}\)
Where,
b & d are width, effective depth of the beam
fy is the yield stress
Calculation:
Given,
b = 450 mm, d = 550 mm
Grade of Steel is Fe 500
\({A_{st}} = \frac{{0.85}}{{fy}} \times bd = \frac{{0.85}}{{500}} \times 450\times550\\=420.75\; mm^2\)
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