Question
Download Solution PDFThe mean effective pressure of the diesel cycle having a fixed compression ratio will increase if the cut-off ratio
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Diesel cycle:
Processes in compression engine (diesel cycle) are:
Process 1-2: Reversible adiabatic compression
Process 2-3: Constant pressure heat addition
Process 3-4: Reversible adiabatic expansion
Process 4-1: Constant volume of heat rejection
cut-off ratio:
The cut-off ratio is the ratio of the volume after combustion to the volume before combustion.
Cut-off ratio: \({r_c} = \frac{{{V_3}}}{{{V_2}}}\)
Compression ratio: \({r} = \frac{{{V_1}}}{{{V_2}}} \)
The efficiency of the diesel cycle is given by
\(\eta = 1 - \frac{1}{{{r^{\gamma - 1}}}}\left[ {\frac{{r_c^\gamma - 1}}{{\gamma \left( {{r_c} - 1} \right)}}} \right]\)
The mean effective pressure (pm) which is an indication of the internal work output increases with a pressure ratio at a fixed value of compression ratio and the ratio of specific heats.
The expression for mean effective pressure for diesel cycle,
\({p_m} = \frac{{{p_1}\left[ {\gamma {r^\gamma }\left( {{r_c} - 1} \right) - r\left( {r_c^\gamma - 1} \right)} \right]}}{{\left( {\gamma - 1} \right)\left( {r - 1} \right)}}\)
From the expression,
The mean effective pressure of the diesel cycle having a fixed compression ratio will increase if the cut-off ratio increases.
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