Question
Download Solution PDFAn air standard diesel cycle working with a compression ratio of 13 and cut off takes places at 5 % of the stroke volume. The value of cut off ratio will be
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Fuel cut off = x% of stroke volume
Calculation:
Given:
\(\frac{{{V_1}}}{{{V_2}}} = 13\)
V1 = 13V2
Now,
Fuel cut off = 5% of stroke volume
V3 – V2 = 5% (V1 – V2)
\({V_3} - {V_2} = \frac{5}{{100}}\left( {13{V_2} - {V_2}} \right) = 0.6\;{V_2}\)
V3 = V2 + 0.6V2 = 1.6V2
\(\frac{{{V_3}}}{{{V_2}}} = Fuel\;cut\;off\;ratio = 1.6\)
Last updated on May 28, 2025
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