Question
Download Solution PDFThe maximum dry density and optimum moisture content of a soil is given by 1.65 gm/cc and 20.5% respectively. What is the percentage of air content of soil at OMC, if the specific gravity of particles is given by 2.65?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFUsing the relation,
\({\gamma _d}_{max} = \frac{{G{\gamma _w}}}{{1 + e}}\)
\(1.65 = \frac{{2.65 \times 1}}{{1 + e}}\)
e = 0.606
Using the relation
se = wG
s = \(\frac{{0.205 \times 2.65}}{{0.606}}\)
s = 0.896
ac + s = 1
where, ac = air content
ac = 0.104 = 10.4 %
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