Compaction Test 1 - Weight of hammer = 10 kg, Height of fall = 500 mm, Number of layers = 3, Number of blows per layer =25.

Compaction Test 2- Weight of hammer = 5 kg, Height of fall = 250 mm, Number of layers = 6, Number of blows per layer = 25.

The ratio of compactive energy of compaction test 1 to that of compaction test 2 is:

Concept:

To find the ratio of compactive energy between two compaction tests, we use the formula for compactive energy. The compactive energy is calculated using the weight of the hammer, height of fall, number of blows per layer, and the number of layers.

Calculation:

For Compaction Test 1:

• Weight of hammer ( $W_1$ ) = 10 kg
• Height of fall ( $h_1$ ) = 500 mm = 0.5 m
• Number of layers ( $L_1$ ) = 3
• Number of blows per layer ( $B_1$ ) = 25

Compactive Energy for Test 1:

\( \text{Compactive Energy}_1 = W_1 \times h_1 \times B_1 \times L_1 \)

\( \text{Compactive Energy}_1 = 10 \times 0.5 \times 25 \times 3 \)

\( \text{Compactive Energy}_1 = 375 \, \text{kg} \cdot \text{m} \)

For Compaction Test 2:

• Weight of hammer ( $W_2$ ) = 5 kg
• Height of fall ( $h_2$ ) = 250 mm = 0.25 m
• Number of layers ( $L_2$ ) = 6
• Number of blows per layer ( $B_2$ ) = 25

Compactive Energy for Test 2:

\( \text{Compactive Energy}_2 = W_2 \times h_2 \times B_2 \times L_2 \)

\( \text{Compactive Energy}_2 = 5 \times 0.25 \times 25 \times 6 \)

\( \text{Compactive Energy}_2 = 187.5 \, \text{kg} \cdot \text{m} \)

Ratio of Compactive Energy (Test 1 to Test 2):

\( \text{Ratio} = \frac{\text{Compactive Energy}_1}{\text{Compactive Energy}_2} \)

\( \text{Ratio} = \frac{375}{187.5} \)

\( \text{Ratio} = 2 \)