The magnetisation branch of an equivalent circuit of a transformer is drawn in ________ with supply voltage.

The correct answer is option 3):(parallel only)

Concept:

The equivalent circuit of the transformer is

I₁ = Primary winding current

I₂ ' =Secondary winding current referred to the primary side

I₀=NO-load current

\(\overrightarrow {{I_1}} = \overrightarrow {{I_0}} + \overrightarrow {{I_2}'}\)

\(\begin{array}{l} \overrightarrow {{I_0}} = \overrightarrow {{I_w}} + \overrightarrow {{I_m}} \\ {I_O} = \sqrt {I_w^2 + I_m^2} \end{array}\)

I_w= Core loss component

I_m=magnetizing component No-load current is almost the same when we apply the load also.

The magnetizing branch circuit is connected in parallel to the supply voltage as the No-load current is constant while we apply load also. Therefore Core loss is also constant as I₀ remains constant