Question
Download Solution PDFThe magnetic field due to a straight current-carrying wire is-
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
- Magnetic field due to a straight current-carrying conductor: Biot-Savart Law
Magnetic field B at a radial distance r, due to a wire carrying current is given by:
\(B = \frac{μ_0I}{2π r}\)
Where μ0 is the permeability of free space (4π × 10-7 Tm/A), and I is the current.
EXPLANATION:
Magnetic field intensity, \(B = \frac{μ_0I}{2π r}\)
\(⇒ B ∝ I\)
- Thus, the magnetic field is directly proportional to the current in the wire.
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