Question
Download Solution PDFThe domain of sin-1 \(\left( {\frac{{x + 1}}{3}} \right)\)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
sin-1y is defined for y ∈ [-1, 1]
∴ sin-1 \(\left( {\frac{{x + 1}}{3}} \right)\) is defined for \(\frac{x+1}{3}\in [-1,1]\)
⇒ \(-1\leq \frac{x+1}{3}\leq 1\)
⇒ \(-3\leq x+1\leq 3\)
⇒ \(-3-1\leq x\leq 3-1\)
⇒ \(-4\leq x\leq 2\)
Hence, the domain of sin-1 \(\left( {\frac{{x + 1}}{3}} \right)\) is [-4, 2].
Last updated on Jun 19, 2025
-> The AAI ATC Exam 2025 will be conducted on July 14, 2025 for Junior Executive..
-> AAI JE ATC recruitment 2025 application form has been released at the official website. The last date to apply for AAI ATC recruitment 2025 is May 24, 2025.
-> AAI JE ATC 2025 notification is released on April 4, 2025, along with the details of application dates, eligibility, and selection process.
-> A total number of 309 vacancies are announced for the AAI JE ATC 2025 recruitment.
-> This exam is going to be conducted for the post of Junior Executive (Air Traffic Control) in the Airports Authority of India (AAI).
-> The Selection of the candidates is based on the Computer-Based Test, Voice Test and Test for consumption of Psychoactive Substances.
-> The AAI JE ATC Salary 2025 will be in the pay scale of Rs 40,000-3%-1,40,000 (E-1).
-> Candidates can check the AAI JE ATC Previous Year Papers to check the difficulty level of the exam.
-> Applicants can also attend the AAI JE ATC Test Series which helps in the preparation.