The correct order of the reactions involved in the following transformation is

Concept:

→ Michael addition involves the formation of a reactive intermediate, which can be either an enolate or an enamine, followed by its attack on the alpha,beta-unsaturated carbonyl compound.

The resulting product is often a beta-keto carbonyl compound, which can be further modified through various chemical reactions.

→ Aldol condensation involves the nucleophilic addition of an enolate ion to the carbonyl group of another carbonyl compound, followed by dehydration to form a double bond between the alpha and beta carbons of the resulting aldol product.

The reaction can be catalyzed by a variety of bases, including hydroxide, alkoxide, and amine bases.

→ The Quasi-Favorskii rearrangement involves the conversion of a beta-hydroxy ketone or aldehyde to an alpha, beta-unsaturated ketone or aldehyde through a base-catalyzed intramolecular rearrangement. It is called "quasi" because it is similar to the Favorskii rearrangement but occurs through a different mechanism.

The mechanism of the Quasi-Favorskii rearrangement involves the deprotonation of the beta-hydroxy group by a base, followed by intramolecular attack of the oxygen atom on the adjacent carbonyl group.

The resulting intermediate then undergoes a proton transfer and elimination of the leaving group, leading to the formation of the alpha, beta-unsaturated carbonyl compound.

Explanation: 

Conclusion:
The correct answer is option 3.