The correct match for the molecules given in Column P with the spectral data given in Column Q is

Column P		Column Q
A.	Ethyl acetate	i.	Two singlets in 1H NMR
B.	2-chloropentane	ii.	Peak intensity at M:(M+2) is 3:1 in EI-MS
C.	1,2-dibromo-2-methylpropane	iii.	Absorption band at 1740 cm-1 in IR

Concept:

• Infrared (IR) absorption bands are specific regions in the infrared spectrum where molecules absorb electromagnetic radiation at characteristic frequencies. These absorption bands arise due to the vibrational motion of atoms within a molecule. As molecules absorb infrared radiation, they undergo vibrational transitions between different energy levels, leading to the absorption of specific frequencies of light. Different types of chemical bonds and functional groups have characteristic vibrational frequencies. By analyzing the positions and intensities of IR absorption bands, we can identify the presence of certain functional groups in a molecule.
• ¹H NMR is a fundamental technique in organic chemistry, used for compound identification, structural elucidation, and quantitative analysis. It's particularly valuable in determining molecular structure and monitoring chemical reactions.
• In mass spectrometry, peak intensity refers to the height or size of a peak on a mass spectrum. Mass spectrometry is an analytical technique used to determine the mass-to-charge ratio (m/z) of ions in a sample. The resulting mass spectrum provides information about the composition and structure of molecules in the sample.

Explanation:

1.    IR absorption band of Ester is ~ 1740 cm^-1.

2. No H-atom is present in C-2 carbon atom, therefore neighboring carbon atoms will show singlet in ¹H NMR.

Conclusion:

Hence, the correct match for the following molecules is A-iii, B-ii, C-i.