The absolute bending moment in a simply supported beam of span 10 m due to a moving load of 40 kN/m spanning over 5 m is

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BPSC AE Paper 5 (Civil) 11 Nov 2022 Official Paper
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  1. 375 kN-m at midpoint
  2. 375 kN-m at 3.75 m from end A
  3. 500 kN-m at mid-span
  4. 375 kN-m at 2.5 m from end A

Answer (Detailed Solution Below)

Option 1 : 375 kN-m at midpoint
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Explanation:
The absolute maximum bending moment will occur at the centre when the load is spread equally on either side of the centre.

\(\begin{array}{l} {M_{max}}\; = \;\frac{{wa}}{4}\left( {L - \frac{a}{2}} \right)\\ \; = \;\frac{{40 \times 5}}{4} \times \left( {10 - \frac{5}{2}} \right) \end{array}\)

= 50 × 7.5 = 375 KN-m at centre
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