Question
Download Solution PDFThe 3-ϕ, Y - load of impedances each (6 + j9) is supplied through a line having an impedance of (1 + j2) Ω. The supply voltage is 400 volts 50 Hz. Determine the line current.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation:
Load impedance = 6 + j9
Line impedance = 1 + j2
Total impedance = 7 + j11
Magnitude of total impedance = 13.038 Ω
Supply voltage (VS) = 400 V
Line current \( = \frac{{400}}{{\sqrt 3 \times 13.038}} = 17.7\;A\)Last updated on May 29, 2025
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