Question
Download Solution PDFధ్వని తరంగం యొక్క పౌనఃపుణ్యం 50 Hz మరియు దాని తరంగదైర్ఘ్యం 4 మీ. 3 సెకన్లలో ధ్వని తరంగం ప్రయాణించే దూరం ఎంత?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFసరైన సమాధానం 600 మీ.
ఇక్కడ ఇవ్వబడింది:
పౌనఃపుణ్యం = 50 Hz,
తరంగదైర్ఘ్యం = 4 మీ.
కాబట్టి, తరంగ వేగం = పౌనఃపుణ్యం × తరంగదైర్ఘ్యం
= 50 × 4
= 200 మీ/సె.కాబట్టి ధ్వని తరంగం 3 సెకన్లలో ప్రయాణించే దూరం:
200 × 3
= 600 మీ.
Last updated on Jun 7, 2025
-> RRB JE CBT 2 answer key 2025 for June 4 exam has been released at the official website.
-> Check Your Marks via RRB JE CBT 2 Rank Calculator 2025
-> RRB JE CBT 2 admit card 2025 has been released.
-> RRB JE CBT 2 city intimation slip 2025 for June 4 exam has been released at the official website.
-> RRB JE CBT 2 Cancelled Shift Exam 2025 will be conducted on June 4, 2025 in offline mode.
-> RRB JE CBT 2 Exam Analysis 2025 is Out, Candidates analysis their exam according to Shift 1 and 2 Questions and Answers.
-> The RRB JE Notification 2024 was released for 7951 vacancies for various posts of Junior Engineer, Depot Material Superintendent, Chemical & Metallurgical Assistant, Chemical Supervisor (Research) and Metallurgical Supervisor (Research).
-> The selection process includes CBT 1, CBT 2, and Document Verification & Medical Test.
-> The candidates who will be selected will get an approximate salary range between Rs. 13,500 to Rs. 38,425.
-> Attempt RRB JE Free Current Affairs Mock Test here
-> Enhance your preparation with the RRB JE Previous Year Papers.