బెంజీన్లో వరుసగా σ మరియు π బంధాల సంఖ్య:

This question was previously asked in
RRB ALP Previous Paper 6 (Held On: 13 Aug 2018 Shift 1)
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  1. 12 మరియు 3
  2. 3 మరియు 3
  3. 6 మరియు 3
  4. 9 మరియు 3

Answer (Detailed Solution Below)

Option 1 : 12 మరియు 3
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  • 1825లో బెంజీన్‌ను మైఖేల్ ఫెరడే వేరు చేశాడు.
  • బెంజీన్ యొక్క పరమాణు సూత్రం C 6 H 6 , అధిక స్థాయి అసంతృప్తతను సూచిస్తుంది.
  • బెంజీన్ 12 σ మరియు 3 π బంధాలను కలిగి ఉంది.
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