Question
Download Solution PDFf(x) = \(\rm \left(x+{1\over x}\right)^2 \) అనే ప్రమేయాన్ని అవకలనం చేయండి
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFభావన:
- \(\rm d\over dx\)xn = nxn-1
- \(\rm d\over dx\)sin x = cos x
- \(\rm d\over dx\)cos x = -sin x
- \(\rm d\over dx\)ex = ex
- \(\rm d\over dx\)ln x = \(\rm1\over x\)
- \(\rm d\over dx\)(ax + b) = a
- \(\rm d\over dx\)tan x = sec2 x
శృంఖల నియమం: y అనేది u యొక్క ప్రమేయం మరియు u అనేది x యొక్క ప్రమేయం అయితే
- \(\rm {dy\over dx} = {dy\over du}\times {du\over dx}\)
గణన:
f(x) = \(\rm \left(x+{1\over x}\right)^2 \)
f(x) = \(\rm \left(x^2+{1\over x^2}+2\right) \)
f(x) = x2 + x-2 + 2
x దృష్ట్యా అవకలనం చేయడం
f'(x) = \(\rm d\over dx\)f(x)
f'(x) = \(\rm d\over dx\)(x2 + x-2 + 2)
f'(x) = \(\rm d\over dx\)x2 + \(\rm d\over dx\)x-2 + \(\rm d\over dx\)2
f'(x) = (2x) + (-2x-3) + 0
f'(x) = \(\boldsymbol{\rm 2\left(x - {1\over x^3}\right)}\)
Last updated on May 21, 2025
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