Question
Download Solution PDFSix analog information signals each band-limited to 4 kHz, are required to be time-division multiplexed and transmitted by a TDM system. The minimum transmission bandwidth and the signalling rate of the PAM/TDM channel are respectively.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
The bit rate for a PAM/TDM system is given by
Rb = nfs
Where
Rb = Bit rate/Signaling rate
n = number of bits in the encoder
fs = sampling frequency
From Nyquist criteria
fs = 2fm
Where fm = message signal frequency
Minimum transmission Bandwidth (B.W.) = nfm ----(1)
Rb = nfs ----(2)
Given:
fm = 4 kHz
n = 6
Minimum transmission Bandwidth (B.W.) is given by equation (1)
B.W. = 6 × 4 = 24 kHz
fs = 2 × 4 = 8 kHz
Signaling rate is given by equation (2):
Rb = 6 × 8 = 48 kHz
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