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PQRS is a rhombus. The each sides of it is 40 cm. If PR = 64 cm and QS = (8x + 8). Then, the value of x is -

  1. 6
  2. 5
  3. 4
  4. 7

Answer (Detailed Solution Below)

Option 2 : 5
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Detailed Solution

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PR = 64 cm

Thus, PO = RO = 32 cm

QS = (8x + 8) cm

Thus, QO = OS = (4x + 4) cm

In Δ SOR –

⇒ 

⇒ 402 – 322 = (4x + 4)2

⇒ 4x + 4 = 24

⇒ 4x + 4 = 24

⇒ 4x = 20

⇒ x = 5 cm

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