Question
Download Solution PDFPipe A can fill an empty tank in 18 hours and pipe B can fill the same empty tank in 24 hours. If both the pipes are opened simultaneously, how much time (in hours) will they take to fill the empty tank?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Pipes A can fill and B can fill a tank in 18 hours and 24 hours respectively..
Concept used:
Entire work = Work done hourly × Total time taken (in hours)
Calculation:
Total capacity = LCM (18, 24) = 72
Now,
Pipe A fill hourly by = 72 ÷ 18 = 4 units
Pipe B fills hourly by = 72 ÷ 24 = 3 units
The total tank will be filled in:
⇒ 72/(4 + 3)
⇒ 10(2/7) hours
They will take to fill the empty tank in 10(2/7) hours.
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