Question
Download Solution PDFसमांतरभुज चौकोन PQRS मध्ये, P आणि Q च्या सलग कोनांचे दुभाजक T ला छेदतात. ∠PTQ चे माप काय आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेली माहिती:
PQRS हा समांतरभुज चौकोन आहे.
वापरलेली संकल्पना:
समांतरभुज चौकोनात, कोनाची बेरीज 180 \(^\circ\) आहे.
गणना:
\(\angle\) PQT= \(\angle\) Q/2
\(\angle\) QPT= \(\angle\) P/2
\(\angle\) P+ \(\angle\) Q=180
बदली करणे,
2 \(\angle\) PQT+2 \(\angle\) QPT = 180
\(\angle\) PQT+ \(\angle\) QPT = 90
पण , \(\angle\) PQT+ \(\angle\) QPT+ \(\angle\) PTQ=180(आंतरीक कोनाची बेरीज 180 आहे)
म्हणून \(\angle\) PTQ = 180 - 90 = 90°
∴ पर्याय 3 हे योग्य उत्तर आहे.
Last updated on Jun 30, 2025
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