जर एक दुकानदार कमी वजन वापरून फळांच्या खरेदी-विक्रीमध्ये 12% पर्यंत फसवणूक करतो, तर त्याचा एकूण शेकडा नफा किती?

A. 25.25

B. 27.27

C. 25.75

D. 25.5   

This question was previously asked in
NTPC Tier I (Held On: 7 Apr 2016 Shift 3)
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  1. B
  2. A
  3. C
  4. D

Answer (Detailed Solution Below)

Option 1 : B
Free
RRB NTPC CBT-I Official Paper (Held On: 4 Jan 2021 Shift 1)
100 Qs. 100 Marks 90 Mins

Detailed Solution

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दिलेल्याप्रमाणे:

खरेदी आणि विक्री करताना फसवणूक टक्केवारी = 12%

वापरलेले सूत्र:

नफा % = [(वि.किं - ख.किं)/ख.किं × 100]

गणना:

दुकानदार फसवणूक करून 100 ग्रॅमऐवजी 112 ग्रॅम माल घेतो

आणि तो 100 ग्रॅम ऐवजी 88 ग्रॅम विकतो

प्रश्नानुसार

वि.किं/ख.किं = (112 × 100)/(100 × 88)

⇒ 14/11

नफा = वि.किं - ख.किं

⇒ 14 - 11 = 3

नफ्याची टक्केवारी = (3/11) × 100%

⇒ 27.27%

∴ दुकानदाराला 27.27 % नफा होतो.

खरेदी आणि विक्री करताना दुकानदार वजनात 12% फसवणूक करतो

दुकानदाराची खरेदी किंमत = [100 × (100 - 12)]/100

⇒ 88

दुकानदारासाठी विक्री किंमत = [100 × (100 + 12)]/100

⇒ 112

नफा % = [(वि.किं - ख.किं)/ख.किं] × 100%

⇒ [(112 - 88)/88] × 100%

⇒ (24/88) × 100%

⇒ 27.27%

∴ दुकानदाराला 27.27% नफा होतो.

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