Question
Download Solution PDFजर एक दुकानदार कमी वजन वापरून फळांच्या खरेदी-विक्रीमध्ये 12% पर्यंत फसवणूक करतो, तर त्याचा एकूण शेकडा नफा किती?
A. 25.25
B. 27.27
C. 25.75
D. 25.5
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
खरेदी आणि विक्री करताना फसवणूक टक्केवारी = 12%
वापरलेले सूत्र:
नफा % = [(वि.किं - ख.किं)/ख.किं × 100]
गणना:
दुकानदार फसवणूक करून 100 ग्रॅमऐवजी 112 ग्रॅम माल घेतो
आणि तो 100 ग्रॅम ऐवजी 88 ग्रॅम विकतो
प्रश्नानुसार
वि.किं/ख.किं = (112 × 100)/(100 × 88)
⇒ 14/11
नफा = वि.किं - ख.किं
⇒ 14 - 11 = 3
नफ्याची टक्केवारी = (3/11) × 100%
⇒ 27.27%
∴ दुकानदाराला 27.27 % नफा होतो.
खरेदी आणि विक्री करताना दुकानदार वजनात 12% फसवणूक करतो
दुकानदाराची खरेदी किंमत = [100 × (100 - 12)]/100
⇒ 88
दुकानदारासाठी विक्री किंमत = [100 × (100 + 12)]/100
⇒ 112
नफा % = [(वि.किं - ख.किं)/ख.किं] × 100%
⇒ [(112 - 88)/88] × 100%
⇒ (24/88) × 100%
⇒ 27.27%
∴ दुकानदाराला 27.27% नफा होतो.
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