Question
Download Solution PDFजर 4-ध्रुवीय इंडक्शन मोटरचा वेग 1800 rpm असेल, तर मोटर किती वारंवारितेवर कार्यरत आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
समकालिक गति मिळविण्याचे सूत्र
\({N_s} = \frac{{120f}}{P}\)
येथे,
f = Hz मध्ये पुरवठा वारंवारता
P = ध्रुवांची संख्या
Ns= rpm मध्ये समकालिक गति
गणना:
दिलेले -
Ns = 1800 rpm, P = 4
\(\therefore {1800} = \frac{{120 \times f}}{{4}}\)
f = 60 Hz
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